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RE: Simple XSL Question
- To: xsl-list at mulberrytech dot com
- Subject: RE: Simple XSL Question
- From: sara dot mitchell at ps dot ge dot com
- Date: Fri, 3 Nov 2000 13:22:14 -0400 (EST)
- Reply-To: xsl-list at mulberrytech dot com
Add the predicate in your XPath expression, so it becomes:
<xsl:value-of select="count(//tablelayout/column[@nr='2']/*)"/>
Sara
> -----Original Message-----
> From: Rob van der Zeijden [mailto:r.zeijden@tiscon.de]
> Sent: Thursday, November 02, 2000 1:22 PM
> To: XSL-List@mulberrytech.com
> Subject: Simple XSL Question
>
>
> Hi,
>
> xml fragement:
>
> <tablelayout>
> <column nr='1'>
> <columnwidth1>9cm</columnwidth1>
> <columnwidth2>7cm</columnwidth2>
> <columnwidth3>3cm</columnwidth3>
> </column>
> <column nr='2'>
> <columnwidth1>9cm</columnwidth1>
> </column>
> </tablelayout>
>
>
> How can I count all the children of the element column where nr = 2?
> Should be something like this:
> <xsl:value-of select="count(//tablelayout/column/*)"/> the
> only thing is that the nr=2
> is not handled yet.
>
> Thanks Rob
>
>
>
>
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>
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