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Re: xsl to xsl (xsl creating xsl ouput)
- To: xsl-list at mulberrytech dot com
- Subject: Re: xsl to xsl (xsl creating xsl ouput)
- From: Oliver Becker <obecker at informatik dot hu-berlin dot de>
- Date: Tue, 5 Sep 2000 19:15:11 +0200 (MET DST)
- Reply-To: xsl-list at mulberrytech dot com
> <?xml version='1.0' encoding="UTF-8"?>
> <x:stylesheet xmlns:x="http://www.w3.org/1999/XSL/Transform"
> xmlns:xsl="anything" version="1.0">
> <x:output method="xml" indent="yes"/>
> <x:namespace-alias stylesheet-prefix="xsl" result-prefix="x"/>
>
> <!-- everything between the x:template tags
> is outputted to the new stylesheet
> -->
>
> <x:template match="/">
> <xsl:stylesheet version="1.0">
> <xsl:template match="/">
> <xsl:value-of select="foobar"/>
> </xsl:template>
>
> <!-- Create the include lines??? -->
> <x:for-each select="//INCLUDE">
> <xsl:include>
> <xsl:attribute name="href">
> <x:value-of select="."/>
> </xsl:attribute>
^^^
This should be <x:attribute>
> </xsl:include>
> </x:for-each>
>
> </xsl:stylesheet>
> </x:template>
> </x:stylesheet>
After applying the "patch" Saxon outputs
<?xml version="1.0" encoding="utf-8"?>
<x:stylesheet xmlns:x="http://www.w3.org/1999/XSL/Transform" version="1.0">
<x:template match="/">
<x:value-of select="foobar"/>
</x:template>
<x:include href="include1.xsl"/>
<x:include href="include2.xsl"/>
</x:stylesheet>
Is this the output you expected?
Cheers,
Oliver
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