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> <xsl:value-of select="generate-id(document('genid1.xml')/a/b) = > generate-id(document('genid2.xml')/b)"/> > > <!-- genid1.xml --> > <!DOCTYPE a [ <!ENTITY genid2 SYSTEM "genid2.xml"> ]> > <a> &genid2; </a> > > <!-- genid2.xml --> > <b/> > > Shouldn't this output true? I think it should... I think the spec is explicit, that if two calls on document() use different URIs then you get two distinct documents back. The XPath model doesn't allow a single node to belong to two different documents, so if the documents are distinct, then all the nodes they contain are distinct. To look at it another way, an entity reference creates a copy of the referenced tree, not a link to it. Mike Kay XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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