URGENT : Substitue value of xsl:variable into output !!!

["Mahesh Nanavate" <mahesh dot nanavate at ecapsol dot com>]

Hi Everybody,

I have one problem :

	Consider the following XML snippet:
		---
		---
		<ItemList>
		<oneItem>
			<ItemID>1212</ItemID>
			<ItemName>XYZ</ItemName>
			<Qty>1</Qty>
		</oneItem>
		</ItemList>
		---
		---
	Consider the following XSL snippet:
		---
		---
	<xsl:template match="oneItem">
		<p><xsl:value-of select="ItemName" /><br/>
			<xsl:variable name="inVar" select="concat('q',ItemID)"/>
			<input name="$inVar" value="{Qty}" type="number"/>	<br/>
		  	 <anchor>Change
				<go
ref="http://10.10.10.94:7001/servlet?mySvc=myApp&amp;myP1={ItemID}&amp;myP2=
$inVar"></go>
	  	 	 </anchor>
		</p>
	</xsl:template>
		---
		---

	My Problem is that I am not able to substitute the value of the
xsl:variable with name inVar
	into 'name' attribute of the input element.
	Also I require that the myP2 be assigned a value of concat('$',value of
inVar).

	The depicted code is not substituting the value of inVar instead it's
giving the string as it is.

	Any help in this regard is most appreciated ,

	Thanks in advance,
	Mahesh.


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