This is the mail archive of the
xsl-list@mulberrytech.com
mailing list .
2 xml from one xsl
- To: "'xsl-list at mulberrytech dot com'" <xsl-list at mulberrytech dot com>
- Subject: 2 xml from one xsl
- From: "Selva, Francis" <Francis dot Selva at purchasepro dot com>
- Date: Tue, 18 Apr 2000 16:28:50 -0700
- Reply-To: xsl-list at mulberrytech dot com
Please ignore the below question cause I was looking at the wrong
output.This was not working for me.Sorry for the confusion.So I still need
help in this regard.
Francis
*******************************
I solved the problem by doing this.Im getting the right output.But I want
to know whether this is the right way or there is a easy way to do what I
need.
<xsl:template match="/">
<xsl:apply-templates select="document('bw.xml')"/>
</xsl:template>
<xsl:template match="/">
all my layout stts
</xsl:template>
Which one is better?.To create one template match and then giving all the
node names in the condition while getting the values or having different
templates match for each category?
***********************************
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list