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setStylesheetParameter() question
- To: "XSL - Mulberry (E-mail)" <XSL-List at mulberrytech dot com>, "Xml-Apache (E-mail)" <general at xml dot apache dot org>
- Subject: setStylesheetParameter() question
- From: Brian Dupras <briand at centera dot com>
- Date: Wed, 23 Feb 2000 10:11:07 -0700
- Reply-To: xsl-list at mulberrytech dot com
Using Xalan and Xerces, I'm tring to send into the XSLT a set of strnig
parameters. Here's what I've got:
xsltProcessor.setStylesheetParam("testing", "'testing val'"); //note the
single quotes
<xsl:template match="/">
<xsl:apply-templates>
<xsl:with-param name="testing"/>
</xsl:apply-templates>
</xsl:template>
<xsl:template match="someelement">
<xsl:param name="testing"/>
<xsl:value-of select="$testing"/>
</xsl:template>
I know the secont template is getting called because the other stuff that's
in there (in my real one) is being output. How do I output the parameter
that I sent in?
Brian Dupras
Centera Information Systems, Inc.
phone 303.381.4420 (direct)
phone 303.939.0200 (operator)
fax 303.939.0111
web http://www.centera.com
email briand@centera.com
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