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Re: $return in wildcarded void functions
dsmith wrote:
> > [...]
> > if ($?var) { use($!var) } // works even if $var would fail to translate
>
> Ah, the idea makes sense now. But, how would the above translate?
$?var - to a literal constant
$!var - to literal 0 if $?var was 0, or else to whatever $var would have
> Would the entire statement get deleted (if $var didn't exist)?
Could be in the future, as a special case of dead code elimination.
- FChE