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On 12/05/17 13:02, tomas@tuxteam.de wrote: > On Fri, May 12, 2017 at 11:56:40AM +0200, alleswirdbesser@posteo.de wrote: >> It is valid ANSI C code and it makes sense. And it is a pointer, >> like in the header: >> extern int inet_aton (const char *__cp, struct in_addr *__inp) __THROW; >> The compiler accepted it as well. > > No. Sorry to be a bit blunt, but I think you haven't understood C. The language itself does not express what should happen here. A pointer looks the same as a pointer to allocated store. Of course, a developer familiar with C will infer the latter because if you were going to allocate in the function you'd pass in a pointer to pointer - but, again, here, the language is not itself *actually explicitly expressing in what you actually write* what's what. A pointer is a pointer is a pointer :-)
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