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Jakub Jelinek <jakub@redhat.com> writes: > y = obstack_alloc (x, n); > ... > obstack_free (x, y); > z = obstack_alloc (x, m); > that if m <= n, then z == y. Writing like this only calls for errors. Why don't use simply use obstack_blank (x, y); ... obstack_blank (x, m - y); z = obstack_finish (x); This will always work. I'll try to handle your patch this way in case you don't beat me. -- ---------------. ,-. 1325 Chesapeake Terrace Ulrich Drepper \ ,-------------------' \ Sunnyvale, CA 94089 USA Red Hat `--' drepper at redhat.com `------------------------
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