RE: Compiling procedures questions

["Crystal, Mayer" <mayer dot crystal at gs dot com>]

Per, Dominique:

	That was it.  It is now happily compiling and running :).  Thanks
for all your explanations and help.


Mayer


-----Original Message-----
From: Per Bothner [mailto:per@bothner.com] 
Sent: Tuesday, September 28, 2004 3:14 PM
To: Crystal, Mayer
Cc: 'kawa@sources.redhat.com'
Subject: Re: Compiling procedures questions


Crystal, Mayer wrote:

> 
> When I run the main of KawaTest the output of the println statement 
> is:
> 
> 	Procedure value = #<procedure proc1?>
> 
> What I was trying to do though was to get the result as true or false.

It is.  #<procedure proc1?> is a true value.

R5RS says:

library syntax:  (or <test1> ...)

The <test> expressions are evaluated from left to right, and the value 
of the first expression that evaluates to a true value (see section 
6.3.1) is returned.

and:

The standard boolean objects for true and false are written as #t and 
#f. What really matters, though, are the objects that the Scheme 
conditional expressions (if, cond, and, or, do) treat as true or false. 
The phrase ``a true value'' (or sometimes just ``true'') means any 
object treated as true by the conditional expressions, and the phrase 
``a false value'' (or ``false'') means any object treated as false by 
the conditional expressions.

Of all the standard Scheme values, only #f counts as false in 
conditional expressions. Except for #f, all standard Scheme values, 
including #t, pairs, the empty list, symbols, numbers, strings, vectors, 
and ***procedures***, count as true.

You probably meant:

     private static final String TEST_RULE = "(or (proc1?) (or (proc2?) 
(proc3?)))";

-- 
	--Per Bothner
per@bothner.com   http://per.bothner.com/