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[Bug libc/12437] New: scanf behavior differs from WG14/N1256 Committee Draft â Septermber 7, 2007
- From: "hjl.tools at gmail dot com" <sourceware-bugzilla at sourceware dot org>
- To: glibc-bugs at sources dot redhat dot com
- Date: Tue, 25 Jan 2011 20:01:43 +0000
- Subject: [Bug libc/12437] New: scanf behavior differs from WG14/N1256 Committee Draft â Septermber 7, 2007
- Auto-submitted: auto-generated
http://sourceware.org/bugzilla/show_bug.cgi?id=12437
Summary: scanf behavior differs from WG14/N1256 Committee Draft
â Septermber 7, 2007
Product: glibc
Version: 2.13
Status: NEW
Severity: normal
Priority: P2
Component: libc
AssignedTo: drepper.fsp@gmail.com
ReportedBy: hjl.tools@gmail.com
Page 300 in
http://www.open-std.org/jtc1/sc22/wg14/www/docs/n1256.pdf
says "100e" shouldn't match "%f". But I got
[hjl@gnu-6 tmp]$ cat s.c
#include <stdio.h>
int main()
{
int count;
float quant;
char buf[100];
count = fscanf(stdin, "%f%s", &quant, buf);
printf ("quant = %lf\n",quant );
printf ("count = %d\n", count);
printf ("string = %s\n", buf);
return 0;
}
[hjl@gnu-6 tmp]$ gcc s.c
[hjl@gnu-6 tmp]$ cat x.input
100ergs of energy
[hjl@gnu-6 tmp]$ ./a.out < x.input
quant = 100.000000
count = 2
string = rgs
[hjl@gnu-6 tmp]$
I was told that Windows and MacOS behave the same as glibc.
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