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Re: GDB can't parse variables named "memory" or "array"?
I filed https://sourceware.org/bugzilla/show_bug.cgi?id=22231
On Fri, 2017-09-29 at 16:17 -0400, Paul Smith wrote:
> On Fri, 2017-09-29 at 14:57 -0400, Sergio Durigan Junior wrote:
> > On Friday, September 29 2017, Paul Smith wrote:
> > > I've tried this with lots of different versions of GDB (7.7.1,
> > > 7.11, 7.12, etc.), and none of them work when debugging my programs
> > > (not just my main program but all my unit tests as well):
> > >
> > > (gdb) p memory
> > > A syntax error in expression, near `'.
> > >
> > > (gdb) p array
> > > A syntax error in expression, near `'.
> > You can also enable "set debug parser on" and/or "set debug
> > expression 1" inside your "faulty" GDB and see if it helps with
> > anything.
>
> This gave very useful information, actually. I now see what's
> happening, although I can't understand why no one has noticed this so
> I'm not sure.
>
> Printing "array" or "memory" shows:
>
> (gdb) p memory
> Starting parse
> Entering state 0
> Reading a token: Next token is token FILENAME (bval<0x335a1d0>)
> Shifting token FILENAME (bval<0x335a1d0>)
> Entering state 47
> Reducing stack by rule 107 (line 932):
> $1 = token FILENAME (bval<0x335a1d0>)
> -> $$ = nterm block ()
> Stack now 0
> Entering state 57
> Reading a token: Now at end of input.
> A syntax error in expression, near `'.
>
> The problem appears to be with the C++ header files, which don't have
> extensions. Here's a repro case:
>
> $ cat gdbtest.cpp
> // must include memory
> #include <memory>
>
> class Foo
> {
> char* memory;
> };
>
> Foo foo;
>
> int main(int, char**)
> {
> return 1;
> }
>
> $ g++ --ggdb3 -o gdbtest gdbtest.cpp
>
> $ gdb -n gdbtest
> ...
> (gdb) br 13
> (gdb) run
> (gdb) p foo.memory
> A syntax error in expression, near `'.
>
>
> Note that you have to use -ggdb3 to see the problem; just using -g
> doesn't show the error. Also it ends up that the symbol must be part
> of a class (or probably struct but not tested): if it's a global or
> auto symbol it's interpreted correctly.
>
> Why is GDB even considering a filename to be part of a print
> expression?