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Re: 64bit pointer
- From: Andreas Schwab <schwab at redhat dot com>
- To: freindlyuser at hushmail dot com
- Cc: gdb at sourceware dot org
- Date: Thu, 03 Sep 2009 14:51:06 +0200
- Subject: Re: 64bit pointer
- References: <20090903122141.4BD7DB8043@smtp.hushmail.com>
freindlyuser@hushmail.com writes:
> I didn't know if this was a bug or if I was just doing something
> wrong. Basically when I try to use * to get the value pointed to by
> something it gives me 32 bits of the pointer which is actually a
> 64bit address.
>
>
> (gdb) x/s *($rdi+0x8)
> 0x4210a9b7: <Address 0x4210a9b7 out of bounds>
> (gdb) x/x $rdi+0x8
> 0x3a9b4210b7a4: 0x00003a9b4210a9b7
> (gdb) x/s 0x00003a9b4210a9b7
> 0x3a9b4210a9b7: "The string it points to"
>
> In the above I wanted to read the string pointed to by the pointer
> at $rdi+0x8
>
> Should this be happening?
Since the type of $rdi is not a pointer, gdb is just being helpful and
implicitly converts the value to (int *) before applying the indirection
operator.
> Should I be using a different command or something different to the
> asterisk?
> Is there a work around where I can read the data in
> 0x00003a9b4210a9b7 without having to manually copy and paste (ie:
> in the commands that are executed on a breakpoint).
There are several options:
- Add a cast, {type} is short for *(type *):
(gdb) x/s {char *}($rdi+8)
- Use the $__ convenience variable after examining the address:
(gdb) x/x $rdi+8
(gdb) x/s $__
Andreas.
--
Andreas Schwab, schwab@redhat.com
GPG Key fingerprint = D4E8 DBE3 3813 BB5D FA84 5EC7 45C6 250E 6F00 984E
"And now for something completely different."