Does gdb can handle longjmp in i386 and amd64 now?

[Hui Zhu <teawater at gmail dot com>]

Hi guys,

I try the following code with gdb in i386 and amd64:
#include   <setjmp.h>
#include   <stdio.h>
jmp_buf j;

void
raise_exception (void)
{
	//printf ("exception   raised\n");
	longjmp (j, 1);		/*   jump   to   exception   handler   */
	printf ("this   line   should   never   appear\n");
}

int
main (void)
{
	if (setjmp (j) == 0)
	{
		printf ("''setjmp''   is   initializing   ''j''\n");
		raise_exception ();
		printf ("this   line   should   never   appear\n");
	}
	else
	{
		printf ("''setjmp''   was   just   jumped   into\n");
		/*   this   code   is   the   exception   handler   */
	}

	return 0;
}


In i386, what I got is:

(gdb) start
Temporary breakpoint 1 at 0x80483ff: file 1.c, line 16.
Starting program: /home/teawater/gdb/a.out

Temporary breakpoint 1, main () at 1.c:16
16		if (setjmp (j) == 0)
(gdb) s
18			printf ("''setjmp''   is   initializing   ''j''\n");
(gdb) s
''setjmp''   is   initializing   ''j''
19			raise_exception ();
(gdb)
raise_exception () at 1.c:9
9		longjmp (j, 1);		/*   jump   to   exception   handler   */
(gdb)
0xb7ea3e61 in siglongjmp () from /lib/tls/i686/cmov/libc.so.6
(gdb) s
Single stepping until exit from function siglongjmp,
which has no line number information.
''setjmp''   was   just   jumped   into

Program exited normally.



In amd64, what I got is:
(gdb) start
Temporary breakpoint 1 at 0x4005c3: file 1.c, line 16.
Starting program: /home/teawater/gdb/a.out

Temporary breakpoint 1, main () at 1.c:16
warning: Source file is more recent than executable.
16		if (setjmp (j) == 0)
(gdb) s
18			printf ("''setjmp''   is   initializing   ''j''\n");
(gdb) s
''setjmp''   is   initializing   ''j''
19			raise_exception ();
(gdb)
raise_exception () at 1.c:9
9		longjmp (j, 1);		/*   jump   to   exception   handler   */
(gdb)
''setjmp''   was   just   jumped   into

Program exited normally.


Are this right?

Thanks,
Hui