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Re: Strange case for expect_type


On Wed, Nov 28, 2007 at 03:45:49AM -0500, Paul Hilfinger wrote:
> 
> Can anyone explain this code fragment from evaluate_subexp_standard?
> 
>     case UNOP_IND:
>       if (expect_type && TYPE_CODE (expect_type) == TYPE_CODE_PTR)
> 	expect_type = TYPE_TARGET_TYPE (check_typedef (expect_type));
>       arg1 = evaluate_subexp (expect_type, exp, pos, noside);
> 
> It SEEMS to be saying that if I "expect" type T* from expression *E, then
> I should expect type T from E.  Say what?  Thanks for any help.

It's also got the logic of typedef checking wrong; you're supposed to
check_typedef before using TYPE_CODE, not after.  Doesn't make sense
to me either.  You can probably reach this code easiest by the
function call case.

                  argvec[tem] = evaluate_subexp (TYPE_FIELD_TYPE (type, tem - 1),
                                                 exp, pos, noside);


-- 
Daniel Jacobowitz
CodeSourcery


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