Re: evaluate more complex expressions using gdb

[Bram Kuijper <a dot l dot w dot kuijper at rug dot nl>]

Daniel Jacobowitz wrote:
> On Wed, Jun 27, 2007 at 12:20:09PM +0200, Bram Kuijper wrote:
> > Hi all,
> >
> > again a newbie question: can I also evaluate the result of subtractions, 
> > additions using the display command? Like some pointer arithmetics:
> >
> > display pointer1 - start_pointer
> >
> > If I do this, gdb gives me the following error:
> >
> > Disabling display 6 to avoid infinite recursion.
> > 6: pointer1 - start_pointer = One of the arguments you tried to pass to 
> > operator- could not be converted to what the function wants.
> >
> > Is there any way to to this using gdb?
>
> You probably need some casts.  The error message means GDB found a
> relevant overloaded operator- in your program for one of those types.

I guess that will be a browse through STL's internals then, since I 
substract two std::vector<Type>::iterators from each other.

thanks for the advice,

Bram