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Re: Taking the address of a convenience variable value


On Tue, May 25, 2004 at 12:55:46PM -0400, Paul Dubuc wrote:

In the June 2004 issue of the C/C++ User's Journal (p. 24) there is an article on how to write user-defined commands for gdb to examine the contents of STL vectors, sets and maps. It looks extremely useful, so I decided to try it modifying the commands for use with the GCC STL, but I can't get some of the commands for sets and maps to work. It relies on a tecnique that involves being able to take the address of a convenience variable value, for example:

  set $maptype = &$arg0._M_t._M_header->_M_value_field
  set $maptypep = &$maptype

When I try this the 2nd statement gives me the error message

Attempt to take address of value not located in memory.

As you note, its trying to take the address of a convenience variable - since convenience variables do not live in the inferior they don't have an address.


Does:

 set $maptype = &$arg0._M_t._M_header->_M_value_field
 set $maptypep = &&$arg0._M_t._M_header->_M_value_field

or:

 set $maptype = $arg0._M_t._M_header->_M_value_field
 set $maptypep = &$arg0._M_t._M_header->_M_value_field

make sense?

The other, sigh, possability is that this was a ``feature'' and there's been a regression :-/

Andrew



It doesn't work with gdb 5.3 or 6.1 on Solaris. The author claims that it works on HP-UX, but I don't know why it would be any different.

Is there a way around this? Or is there another source of user-defined commands that can be used to print the contents of STL containers in gdb? Any help would be very much appreciated.


I read that article and was wondering if it was necessary to compile the
STL with -g and not with -O2. I don't think the author mentioned it, but
how else could all of the symbols in the STL work properly with GDB?

What does:


(gdb) paddr &$arg0._M_t._M_header->_M_value_field

display?


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