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Re: Call function in gdb



> With old gdb, I can do
> 
> (gdb) call foo (1)
> 
> Now with gdb in CVS, I got "segmentation fault". Any ideas, BTW,
> I am using Linux/i386.

Not sure what's up --- it works for me:

zenia:play$ $c6/gdb/gdb -nw bar
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To disable command-line taunts, run gdb with "-w".

GNU gdb 4.18.1
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GDB is free software, covered by the GNU General Public License, and you are
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This GDB was configured as "i686-pc-linux-gnu"...
(gdb) break main
Breakpoint 1 at 0x80483e7: file bar.c, line 12.
(gdb) run
Starting program: /home/jimb/play/bar 

Breakpoint 1, main (argc=1, argv=0xbffff524) at bar.c:12
12        printf ("%d\n", bar (argc));
(gdb) p bar(3)
$1 = 4
(gdb) list
7       }
8
9       int
10      main (int argc, char **argv)
11      {
12        printf ("%d\n", bar (argc));
13
14        return 0;
15      }
(gdb) The program is running.  Exit anyway? (y or n) 

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