[Bug c++/16874] Setting a breakpoint on function in anonymous namespace is unnecessarily awkward

["dmalcolm at redhat dot com" <sourceware-bugzilla at sourceware dot org>]

https://sourceware.org/bugzilla/show_bug.cgi?id=16874

--- Comment #16 from Dave Malcolm <dmalcolm at redhat dot com> ---
(In reply to Pedro Alves from comment #15)
> The series above is finally all merged to master.  These are the related
> improvements that you'll find there:

[...]

Thanks for the improvements!

> * Breakpoints on C++ functions are now set on all scopes by default
> 
>   By default, breakpoints on functions/methods are now interpreted as
>   specifying all functions with the given name ignoring missing
>   leading scopes (namespaces and classes).
> 
>   For example, assuming a C++ program with symbols named:
> 
>     A::B::func()
>     B::func()
> 
>   both commands "break func()" and "break B::func()" set a breakpoint
>   on both symbols.

To clarify, if there is a symbol:

      (anonymous namespace)::func()

will "break func" set a breakpoint on it?  (without me having to type or
tab-complete the "(anonymous namespace)" part?)

[...]

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