[Bug c++/21323] New: GDB thinks char16_t and char32_t are signed in C++

["jwakely.gcc at gmail dot com" <sourceware-bugzilla at sourceware dot org>]

https://sourceware.org/bugzilla/show_bug.cgi?id=21323

            Bug ID: 21323
           Summary: GDB thinks char16_t and char32_t are signed in C++
           Product: gdb
           Version: 7.11.1
            Status: UNCONFIRMED
          Severity: normal
          Priority: P2
         Component: c++
          Assignee: unassigned at sourceware dot org
          Reporter: jwakely.gcc at gmail dot com
  Target Milestone: ---

tmp$ cat c.c
#include <uchar.h>
int main()
{
  char16_t u16 = 0xf000;
  char32_t u32 = 0xf0000000;
  return 0;
}
tmp$ gcc c.c -g
tmp$ gdb -q -ex "br 6" -ex run -ex "p u16" -ex "p u32" -ex cont -ex quit a.out 
Reading symbols from a.out...done.
Breakpoint 1 at 0x4004e7: file c.c, line 6.
Starting program: /tmp/a.out 

Breakpoint 1, main () at c.c:6
6         return 0;
$1 = 61440 u''
$2 = 4026531840 U'\xf0000000'
Continuing.
[Inferior 1 (process 1258) exited normally]
tmp$ g++ c.c -g
tmp$ gdb -q -ex "br 6" -ex run -ex "p u16" -ex "p u32" -ex cont -ex quit a.out 
Reading symbols from a.out...done.
Breakpoint 1 at 0x4005a7: file c.c, line 6.
Starting program: /tmp/a.out 

Breakpoint 1, main () at c.c:6
6         return 0;
$1 = -4096 u''
$2 = -268435456 U'\xf0000000'
Continuing.
[Inferior 1 (process 1276) exited normally]

tmp$ gdb --version
GNU gdb (GDB) Fedora 7.11.1-86.fc24
...


The C++ standard is clear that they're unsigned types:

Types char16_t and char32_t denote distinct types with the same size,
signedness, and alignment as uint_least16_t and uint_least32_t, respectively,
in <cstdint>, called the underlying types.







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