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ARM e7t memory layout


Hi all,

For ARM e7t board, when I configure startup type as "ROM", the
included memory layout file is mlt_arm_e7t_rom.ldi/.h, which is,

#include <cyg/infra/cyg_type.inc>

MEMORY
{
    ram : ORIGIN = 0, LENGTH = 0x80000
    rom : ORIGIN = 0x1800000, LENGTH = 0x80000
}

SECTIONS
{
    SECTIONS_BEGIN
    CYG_LABEL_DEFN(__reserved_bootmon) = 0x1800000; . = 
CYG_LABEL_DEFN(__reserved_bootmon) + 0x20000;
    SECTION_rom_vectors (rom, ALIGN (0x8), LMA_EQ_VMA)
    SECTION_text (rom, ALIGN (0x1), LMA_EQ_VMA)
    SECTION_fini (rom, ALIGN (0x4), LMA_EQ_VMA)
    SECTION_rodata (rom, ALIGN (0x4), LMA_EQ_VMA)
    SECTION_rodata1 (rom, ALIGN (0x4), LMA_EQ_VMA)
    SECTION_fixup (rom, ALIGN (0x4), LMA_EQ_VMA)
    SECTION_gcc_except_table (rom, ALIGN (0x4), LMA_EQ_VMA)
    SECTION_fixed_vectors (ram, 0x20, LMA_EQ_VMA)
    SECTION_data (ram, 0x8000, FOLLOWING (.gcc_except_table))
    SECTION_bss (ram, ALIGN (0x4), LMA_EQ_VMA)
    CYG_LABEL_DEFN(__heap1) = ALIGN (0x8);
    SECTIONS_END
}

Since e7t's chip is Samsung KS32C50100, and the chip starts execution
from address 0 after reset, that I am a bit confused as to why the
starting address of ROM section is 0x1800000(which is for RAM?)
rather than 0.

Thanks for any help.

Roturier



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