This is the mail archive of the docbook-apps@lists.oasis-open.org mailing list .


Index Nav: [Date Index] [Subject Index] [Author Index] [Thread Index]
Message Nav: [Date Prev] [Date Next] [Thread Prev] [Thread Next]
Other format: [Raw text]

RE: no wonder i'm confused about the node() functio n


Not having Tidwell's book, I can't comment on that.  Michael Kay's
statement, though, is completely in line with the specification.  The key
explanation is a few lines before what you quoted: "As an expression
<<node()>> is short for <<./child::node()>>, and the only nodes that this
can select are nodes that are children of something."  If you were to write
a template expressly using the namespace axis (e.g. <xsl:template
match="namespace::node()"/>) You could use the node() "NodeTest" to match a
namespace node.

HTH,

Jeff Beal

-----Original Message-----
From: Robert P. J. Day [mailto:rpjday at mindspring dot com]
Sent: Sunday, March 02, 2003 3:02 PM
To: docbook apps list
Subject: DOCBOOK-APPS: no wonder i'm confused about the node() function



"XSLT", Doug Tidwell, p. 51

  "* The node() node test, which selects all nodes in the current
  context, regardless of type.  This includes elements, text, comments
  processing instuctions, attributes, and namespace nodes."

"XSLT Programmer's Reference", 2nd ed., Michael Kay, p. 432

  "Since root nodes, attribute nodes and namespace nodes are never
  children of another node ... they will never be matched by the
  pattern node()."

"http://www.w3.org/TR/xslt";

  "* node() matches any node other than an attribute node and
  the root node"



at this point, i'm scared to read anything else for the fear
of getting a *fourth* opinion.

rday


Index Nav: [Date Index] [Subject Index] [Author Index] [Thread Index]
Message Nav: [Date Prev] [Date Next] [Thread Prev] [Thread Next]