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Re: XSL: Docbook to foreign DTD
- From: Dave Pawson <daveP at dpawson dot freeserve dot co dot uk>
- To: Jochen Hein <jochen at jochen dot org>, docbook-apps at lists dot oasis-open dot org
- Date: Fri, 04 Jan 2002 18:10:44 +0000
- Subject: Re: DOCBOOK-APPS: XSL: Docbook to foreign DTD
At 21:16 03/01/2002 +0100, Jochen Hein wrote:
>I'm converting Docbook into a given DTD and have problems mapping
>xref. It looks pretty easy:
>Docbook: <xref linkend="something"/> is going to be
><xref xlink:href="something"/> in the foreign DTD.
>
>My template
>
><xsl:template match="xref">
> <xref>
> <xsl:attribute name="xlink:href"><xsl:value-of
> select="@linkend"/></xsl:attribute>
> </xref>
></xsl:template>
>
>generates <xref href="something"/>, so I assume that gives me problems
>with some sort of namespace. So my question is, how do I generate an
>attribute name with a colon?
the colon is for namespace seperation.
Either use a qname element or recognise the ns axis,
HTH DaveP