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Re: snprintf() with g++ -std=c++98: error: 'snprintf' was not declared in this scope


On 2012-04-04 10:18, Corinna Vinschen wrote:
On Apr 4 16:54, Denis Excoffier wrote:
-#if !defined(__STRICT_ANSI__) || (__STDC_VERSION__>= 199901L)
+#if !defined(__STRICT_ANSI__) || (__STDC_VERSION__>= 199901L) || (__cplusplus>= 201103L)

How is that supposed to work?


   $ gcc -xc++ -std=c++98 -dM -E -<  /dev/null | grep cplus
   #define __cplusplus 1

   $ gcc -xc++ -std=c++0x -dM -E -<  /dev/null | grep cplus
   #define __cplusplus 1

Actually I'm wondering if that's not a bug in gcc:

It is, and it has been fixed in 4.7.0[1]:


G++ now sets the predefined macro __cplusplus to the correct value,
199711L for C++98/03, and 201103L for C++11.

That being said, there are many such issues in the newlib and Cygwin headers.



Yaakov


[1] http://gcc.gnu.org/gcc-4.7/changes.html

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