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Makefile.in patch -- why?
- To: cygwin-developers at cygwin dot com
- Subject: Makefile.in patch -- why?
- From: Christopher Faylor <cgf at redhat dot com>
- Date: Wed, 12 Sep 2001 11:38:56 -0400
- Reply-To: cygwin-developers at cygwin dot com
Earnie, I don't see how the below change can possibly be right.
I've sent out my configure line many times in the past. If continue to use
it now, I end up with a /usr/usr/include and a /usr/usr/lib directory.
Without a prefix, I assume that I'd end up with something like .../i686-pc-cygwin/usr/lib
rather than .../i686-pc-cygwin/lib .
Can you revert this change, please? I think that you should do whatever needs
doing on the command line.
cgf
Index: Makefile.in
===================================================================
RCS file: /cvs/uberbaum/winsup/w32api/lib/Makefile.in,v
retrieving revision 1.12
retrieving revision 1.13
diff -p -r1.12 -r1.13
*** Makefile.in 2001/09/04 20:56:23 1.12
--- Makefile.in 2001/09/12 14:48:07 1.13
*************** endif
*** 37,44 ****
datadir = @datadir@
infodir = @infodir@
ifneq (,$(findstring cygwin,$(target_alias)))
! inst_includedir:=$(tooldir)/include/w32api
! inst_libdir:=$(tooldir)/lib/w32api
else
inst_includedir:=$(includedir)
inst_libdir:=$(libdir)
--- 37,44 ----
datadir = @datadir@
infodir = @infodir@
ifneq (,$(findstring cygwin,$(target_alias)))
! inst_includedir:=$(tooldir)/usr/include/w32api
! inst_libdir:=$(tooldir)/usr/lib/w32api
else
inst_includedir:=$(includedir)
inst_libdir:=$(libdir)