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Be more liberal in ignoring ARM mapping symbols
- From: Daniel Jacobowitz <drow at false dot org>
- To: binutils at sourceware dot org
- Date: Tue, 11 Apr 2006 12:37:06 -0400
- Subject: Be more liberal in ignoring ARM mapping symbols
I noticed today that the ARM compiler also generates $b mapping symbols.
Rather than continuing to play catch-up, this makes $<character> and
$<character>.<string> be generally ignored. Is this OK?
--
Daniel Jacobowitz
CodeSourcery
2006-04-11 Daniel Jacobowitz <dan@codesourcery.com>
* bfd/cpu-arm.c (bfd_is_arm_mapping_symbol_name): Accept more
mapping symbols.
Index: bfd/cpu-arm.c
===================================================================
RCS file: /cvs/src/src/bfd/cpu-arm.c,v
retrieving revision 1.19.12.1
diff -u -p -r1.19.12.1 cpu-arm.c
--- bfd/cpu-arm.c 11 Apr 2006 15:54:53 -0000 1.19.12.1
+++ bfd/cpu-arm.c 11 Apr 2006 16:25:25 -0000
@@ -405,11 +405,11 @@ bfd_boolean
bfd_is_arm_mapping_symbol_name (const char * name)
{
/* The ARM compiler outputs several obsolete forms. Recognize them
- in addition to the standard $a, $t and $d. */
+ in addition to the standard $a, $t and $d. We are somewhat loose
+ in what we accept here, since the full set is not documented. */
return (name != NULL)
&& (name[0] == '$')
- && ((name[1] == 'a') || (name[1] == 't') || (name[1] == 'd')
- || (name[1] == 'm') || (name[1] == 'f') || (name[1] == 'p'))
+ && (name[1] >= 'a' && name[1] <= 'z')
&& (name[2] == 0 || name[2] == '.');
}