Re: mips address+symbol issue.

[Robert Dewar <dewar at gnat dot com>]

Erik Trulsson wrote:

> Remember that a[i] is just syntactic sugar for *(a+i).

I don't think that's right, I think the intention is that
a[i] is syntactic sugar for *(a+(i)). Nothing else makes
sense. For example you would be saying that you could
not have a subscript of the form x[a==b] since it would
mean *((x+a) == b). That just can't be right.

To me the quoted program is clearly correct, and if it
does not work, it's a compiler bug.

Note that your interpretation would also mean that

   int a[10];
   int x;

   x = 11;
   .. = a[x-2];

would be undefined, and that seems equally implausible.